Question 433184f1

$\frac{1}{\left(x+1\right)\left(4x-5\right)}$

$\frac{3}{3x-6}$

$-\frac{1}{\left(x+1\right)\left(4x-5\right)}$

$\frac{9}{\left(x+1\right)\left(4x-5\right)}$